Consider a titration of a Mn2+ solution with EDTA. The titration is performed at pH 10.0, where the alpha fraction for Y

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899604
Joined: Mon Aug 02, 2021 8:13 am

Consider a titration of a Mn2+ solution with EDTA. The titration is performed at pH 10.0, where the alpha fraction for Y

Post by answerhappygod »

Consider a titration of a Mn2+ solution with EDTA. The
titration is performed at pH 10.0, where the alpha fraction for Y4-
is 0.355. For the MnY2- complex, Kf = 6.2 x 1013.
Calculate the conditional formation constant for MnY2-
(K­’MnY).
Find the concentration of free Mn2+, [Mn2+], in a
solution of 5.50 x 10-4 M MnY2-.
Calculate pNi at the equivalence point of a titration of
50.00 ml of 1.75 x 10-3 M Ni2+ by a 1.75 x 10-3 M EDTA
solution. Both solutions are buffered to a pH of 10.0, where
the alpha fraction for Y4- is 0.355. For the NiY2- complex,
Kf = 4.2 x 1018.
Calculate the concentration (M) of 50.00 mL of an
unknown solution of Mg2+ if 45.00 mL of 0.0100 M EDTA is required
to reach the end point.
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply