Review Step 1: Learning Goal: A parallel plate capacitor goes through 3 steps shown in (Figure 1) Step 1: The gap betwee

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: Review Step 1 Learning Goal A Parallel Plate Capacitor Goes Through 3 Steps Shown In Figure 1 Step 1 The Gap Betwee 1 (217.83 KiB) Viewed 92 times

Review Step 1: Learning Goal: A parallel plate capacitor goes through 3 steps shown in (Figure 1) Step 1: The gap between the two plates is filled with a dielectric slab of a dielectric constant of 6.3. The separation between the two plates d = 0.054 m . The area of each plate is A = 0.036 m2. When the capacitor is fully charged, the amount of charge on each plate is Q1 = 10.0 nC, 1nC 10-9c The gap between the two plates is filled with a dielectric slab of a dielectric constant of 6.3. The separation between the two plates d = 0.054 m . The area of each plate is A = 0.036 m². When the capacitor is fully charged, the amount of charge on each plate is Q1 = 10.0 nC. 1nC = 10-9c Part A - Step 1: what is the capacitance C1? ΑΣ XX V y XX answer format: 1.234 Step 2: The charged capacitor in Step 1 remains connected to the same charging battery. The dielectric slab is removed so that the gap between the two plates is a vacuum. The separation between the two plates is unchanged d = 0.054 m . The area of each plate is unchanged A = 0.036 m2 Use scientific notation -10h, unit is Farad, No NEED to enter unit. capacitance C1 3.717x10-11 Farad = Step 3: The charged capacitor in step 2 is DISCONNECTED from the charging battery. Submit Previous Answers The plate area is unchanged at the original value 0.036 m2. The gap separation is changed to of the original d, d3 = 0.0405 m Correct Part B - Step 1: Find the potenrial difference between the two plates AV1. Format: regular number with 1 digit after the decimal point. Unit is Volt (no need to enter) AV1 = 269.0 V Submit Previous Answers Correct
u Review Part D-Step 1: What the energy stored in the capacitor? Use scientific notation answer format: 1.234-10 unit is Joule Energy in Step 1 = 1.345x10-6 J Learning Goal: A parallel plate capacitor goes through 3 steps shown in (Figure 1) Step 1: The gap between the two plates is filled with a dielectric slab of a dielectric constant of 6.3. The separation between the two plates d = 0.054 m . The area of each plate is A = 0.036 m2 When the capacitor is fully charged, the amount of charge on each plate is Q1 = 10.0 nC, Inc = 10°C Submit Previous Answers ✓ Correct Step 2: Step 2: The charged capacitor in Step 1 remains connected to the same charging battery. The dielectric slab is removed so that the gap between the two plates is a vacuum. The separation between the two plates is unchanged d = 0.054 m . The area of each plate is unchanged A = 0.036 The charged capacitor in Step 1 remains connected to the same charging battery. The dielectric slab is removed so that the gap between the two plates is a vacuum. The separation between the two plates is unchanged d = 0.054 m . The area of each plate is unchanged A = 0.036 m2 - Part E - Step 2: calculate the magnitude of the electric field in the gap, E2 Step 3: The charged capacitor in step 2 is DISCONNECTED from the charging battery The plate area is unchanged at the original value 0.036 m². The gap separation is changed to of the original d, dz = 0.0405 m Format: regular number with 1 digit after the decimal point, unit is Newton/Coulomb N/C (or V/m), No NEED to enter unit. Templates do redo reslet Symbols keyboard shortcuts help exponent subscript fraction square root nth root vector unit vector absolute Value scientific notation delete Close keyboard magnitude E2 V/m 5.9. 10-12 Submit Previous Answers Request Answer Figure (1 of 1 * Incorrect; Try Again; 3 attempts remaining +0, -0, +0, -Q, +0 -Q Part F-Step 2: what is the capacitance C2? Use scientific notation answer format: 1.234-10, unit NEED to enter unit. Farad, No Step 1 Step 2 Step 3 Pearson
Part F-Step 2: what is the capacitance C2? Use scientific notation answer format: 1.234.10" , unit is Farad, No NEED to enter unit Templates um do redo reset o Symbols keyboard shortcuts help capacitance C2 Farad O You have already submitted this answer. Enter a new answer. No credit lost. Try again. Submit Previous Answers Request Answer Part G - Step 2: what is the amount of charge Q2 on each plate? Use scientific notation answer format: 1.234.10h, unit is Coulomb, No NEED to enter unit. Templates undo redo reslet keyboard shortcuts Symbols help, Q2 с = Submit Request Answer