49 [Total 5 marks) 1 eV = 1.6x10-19J me = 9.11*10-31 kg P4: One electron with an energy of 189 eV is moving in a circula

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49 [Total 5 marks) 1 eV = 1.6x10-19J me = 9.11*10-31 kg P4: One electron with an energy of 189 eV is moving in a circula

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49 Total 5 Marks 1 Ev 1 6x10 19j Me 9 11 10 31 Kg P4 One Electron With An Energy Of 189 Ev Is Moving In A Circula 1
49 Total 5 Marks 1 Ev 1 6x10 19j Me 9 11 10 31 Kg P4 One Electron With An Energy Of 189 Ev Is Moving In A Circula 1 (39.54 KiB) Viewed 132 times
49 [Total 5 marks) 1 eV = 1.6x10-19J me = 9.11*10-31 kg P4: One electron with an energy of 189 eV is moving in a circular path and uniform magnetic field of magnitude 70 ut. The magnetic fielded is perpendicular to the velocity vector. Find (a) the frequency of revolution of the electron. [2.5 marks) (b)the radius of the circular path of the electron [2.5 marks)
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