A conducting rod is pulled horizontally with constant force F= 3.90 N along a set of rails separated by d= 0.420 m. A un

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answerhappygod
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A conducting rod is pulled horizontally with constant force F= 3.90 N along a set of rails separated by d= 0.420 m. A un

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A conducting rod is pulled horizontally with constant force F=
3.90 N along a set of rails separated by d= 0.420 m. A uniform
magnetic field B= 0.700 T is directed into the page. There is no
friction between the rod and the rails, and the rod moves with
constant velocity v= 6.50 m/s.
a)Using Faraday's Law, calculate the induced emf around the loop
in the figure that is caused by the changing flux. Assign clockwise
to be the positive direction for emf.
b)The emf around the loop causes a current to flow. How large is
that current? (Again, use a positive value for clockwise
direction.)
c)From your previous results, what must be the electrical
resistance of the loop? (The resistance of the rails is negligible
compared to the resistance of the rod, so the resistance of the
loop is constant.)
d)The rate at which the external force does mechanical work must
be equal to the rate at which energy is dissipated in the circuit.
What is that rate of energy dissipation (power dissipated)?
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