A conducting cod is pulled horizontally with constant force F= 3.60 N along a set of rails separated by = 0.500 m. A un

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A Conducting Cod Is Pulled Horizontally With Constant Force F 3 60 N Along A Set Of Rails Separated By 0 500 M A Un 1 (36.08 KiB) Viewed 62 times

A conducting cod is pulled horizontally with constant force F= 3.60 N along a set of rails separated by = 0.500 m. A un form magnetic field B-0.600 TS directed into the page. There is no friction between the rod and the rails, and the rod moves with constant velocity v= 5.20 m/s х х х х х х X F d х х х х х х for em 15 O х х х Using Faraday's Law, calculate the induced emf around the loop in the figure that is caused by the changing flux. Assign clockwise to be the positive direction When the magnetic Mela is uniform and normal to the plane of the loop, then the flux is of the product of the field and the area. In this problem it is the area that changes with time, not the field. SA Incorrect. Thes 4/12 Previous Thies The emf around the loop causes a current to flow. How large is that current? (Again, use a positive value for clockwise direction.) Remember Fema: Since vis constant, a, sot must be true that the net force on the rod is zero. The pulling force is compensating the force on the rod due to the current through it and the magnetic field Sac An Incorrect. Tries 1/12 Previous Tres From your previous results, what must be the electrical resistance of the loop? (The resistance of the rails is negligible compared to the resistance of the rod, so the resistance of the loop is constant.) fit Tries 0/12 The rate at which the external force does mechanical work must be equal to the rate at which energy is dissipated in the circuit. What is that rate of energy dissipation (power dissipated)?