AV-64.0 V 3. You have two parallel conducting plates which are 20.0 cm long and separated by a distance of 10.0 cm, as s

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answerhappygod
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AV-64.0 V 3. You have two parallel conducting plates which are 20.0 cm long and separated by a distance of 10.0 cm, as s

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Av 64 0 V 3 You Have Two Parallel Conducting Plates Which Are 20 0 Cm Long And Separated By A Distance Of 10 0 Cm As S 1
Av 64 0 V 3 You Have Two Parallel Conducting Plates Which Are 20 0 Cm Long And Separated By A Distance Of 10 0 Cm As S 1 (37.53 KiB) Viewed 55 times
AV-64.0 V 3. You have two parallel conducting plates which are 20.0 cm long and separated by a distance of 10.0 cm, as shown. The potential difference between the plates is 64.0 V. At the instant shown, an electron is 6.80 cm from the left plate moving with a speed of v=4.50 x 10m/s towards the left plate. The electron is speeding up (a) What is the speed of the electron just as it hits the left plate? (4 20.0 cm 6.80 cm 10.0 cm (b) If the potential of the left plate is 20.0 V, what is the potential of the right plate? [1] AV = 64.0 V (c) A different electron, moving with the same initial speed, enters the space between the two plates 6.80 cm from the left plate. The trajectory of the electron is shown, and it just misses the edge of the left plate as it exits the field. How much kinetic energy did that second electron gain as it passed through the field? (Note: You don't need any other information to solve this question.) [2] 6.80 cm
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