Step 1: The gap between the two plates is filled with a dielectric slab of a dielectric constant of 6.3. The separation

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: Step 1 The Gap Between The Two Plates Is Filled With A Dielectric Slab Of A Dielectric Constant Of 6 3 The Separation 1 (75.09 KiB) Viewed 49 times

Step 1: The gap between the two plates is filled with a dielectric slab of a dielectric constant of 6.3. The separation between the two plates d = 0.054 m . The area of each plate is A = 0.033 m² . When the capacitor is fully charged, the amount of charge on each plate is Qı 8.80 nC, 1nC = 10-9 C Step 2: The charged capacitor in Step 1 remains connected to the same charging battery. The dielectric slab is removed so that the gap between the two plates is a vacuum. The separation between the two plates is unchanged d = 0.054 m . The area of each plate is unchanged A = 0.033 m² Step 3: The charged capacitor in step 2 is DISCONNECTED from the charging battery. The plate area is unchanged at the original value 0.033 m² . The gap separation is changed of the original d, dz = 0.0405 m 3 to 4 =

+Q1 -Q+Q2 -Q2 +Q3 -Q3 Step 1 Step 2 Step 3

Step 1: The gap between the two plates is filled with a dielectric slab of a dielectric constant of 6.3. The separation between the two plates d = 0.054 m. The area of each plate is A = 0.033 m". When the capacitor is fully charged, the amount of charge on each plate is Q1 = 8.80 nC. Inc - 10°C Part A - Step 1: what is the capacitance C12 AED Use scientific notation *.10 answer format: 1.234-10", unit is Farad, No NEED to enter unit. ΕΠΙ ΑΣΦ o capacitance Farad C1 Submit Request Answer Part B - Step 1: Find the potenrial difference between the two plates AV. Format: regular number with 1 digit after the decimal point. Unit is volt (no need to enter) ΚΑΙ ΑΣΦ ? ΔV - Submit Request Answer

Part C-Step 1: What is the magnitude of the electric field E, in the gap of the capacitor? Format: regular number with 1 digit after the decimal point, unit is Newton/Coulomb N/C (or V/m), No NEED to enter unit. V AEO 1] ? magnitude E1 V/m = Submit Request Answer Part D - Step 1: What is the energy stored in the capacitor? Use scientific notation answer format: 1.234:10n, unit is Joule V AEO 12 ? Energy in Step 1 = Submit Request Answer

Step 2: The charged capacitor in Step 1 remains connected to the same charging battery. The dielectric slab is removed so that the gap between the two plates is a vacuum. The separation between the two plates is unchanged da 0.054 m. The area of each plate is unchanged A = 0.033 m² Part E - Step 2: calculate the magnitude of the electric field in the gap. Ez Format: regular number with 1 cligit after the decimal point, unit is Newton/Coulomb NC (or V/m), No NEED to enter unit. AED th t ? magnitude E Vim Submit Request Answer Part F-Step 2: what is the capacitance Cy? Use scientific notation answer format: 1.234-10" , unit is Farad, No NEED to enter unit. PHI AΣΦ ? capacitance Farad C2 Submit Request Answer

Part G-Step 2: what is the amount of charge Q2 on each plate? Use scientific notation answer format: 1.234-10", unit is Coulomb, No NEED to enter unit. ΚΑΙ ΑΣΦ ? Q2 = с Submit Request Answer Step 3 The charged capacitor in step 2 is DISCONNECTED from the charging battery. The plate area is unchanged at the original value 0.033 m² . The gap separation is changed to 2 of the original d, d3 = 0.0405 m Part H - Step 3: What is the capacitance C3? Use scientific notation answer format: 1.234.10" , unit is Farad, No NEED to enter unit. ΠΡΕΙ ΑΣφ ? C3 = Farad Submit Request Answer Part I - Step 3: What is the potential difference between the two plates AV3.? Format: regular number with 1 digit after the decimal point. Unit is Volt (no need to enter) TVO AO ? AV3 = V Submit Request Answer