Assume, you have a sensitizer, S, that also works as an electron
acceptor in your design: the zero-
to-zero energy is 2 eV, and its reduction potential, E(0)(S*-/S) =
-0.9 V vs. SCE.
You have a selection of three electron donors. The reduction
potentials of their oxidized forms are:
E(0)(D1*+/D1) = 0.4 V vs. SCE; E(0)(D2*+/D2) = 0.8 V vs. SCE; and
E(0)(D3*+/D3) = 1.2 V vs. SCE.
(Make it easy, and work in eV for energy units. Remember, the
thermal energy at room temperature
is, kBT = 0.025 eV or about)
Calculate DG for the photoinduced charge transfer (charge
separation) between S and D1, S and
D2, and S and D3. For simplicity, ignore the Born solvation energy,
DGS, and the Coulomb work, W.
Assume, you have a sensitizer, S, that also works as an electron acceptor in your design: the zero- to-zero energy is 2
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Assume, you have a sensitizer, S, that also works as an electron acceptor in your design: the zero- to-zero energy is 2
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