- A 1 Rf Wte Rf Wto D Et 0 Rf2 O Wtp D Wty 21 A 75 Kg 1 75 M Tall Person Lays On A 3 Kg 2 M Long Boa 1 (31.37 KiB) Viewed 65 times
a 1 RF Wte RF₂ Wto d ET, = 0) = (RF2)O) - (Wtp)(d) - (Wty)('/21) A 75 kg 1.75 m tall person lays on a 3 kg, 2 m long boa
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a 1 RF Wte RF₂ Wto d ET, = 0) = (RF2)O) - (Wtp)(d) - (Wty)('/21) A 75 kg 1.75 m tall person lays on a 3 kg, 2 m long boa
a 1 RF Wte RF₂ Wto d ET, = 0) = (RF2)O) - (Wtp)(d) - (Wty)('/21) A 75 kg 1.75 m tall person lays on a 3 kg, 2 m long board. The reaction force reading on the scale is 400 N. What is the torque due to the person? 29 43 Nm -735.75 Nm 800 Nm 771.75 Nm
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