Part B: Determination of the Activation Energy (E.) and Frequency factor (A) Reaction Table 5 Temp of Time Temp Relative

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Part B: Determination of the Activation Energy (E.) and Frequency factor (A) Reaction Table 5 Temp of Time Temp Relative

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Part B Determination Of The Activation Energy E And Frequency Factor A Reaction Table 5 Temp Of Time Temp Relative 1
Part B Determination Of The Activation Energy E And Frequency Factor A Reaction Table 5 Temp Of Time Temp Relative 1 (53.03 KiB) Viewed 113 times
Part B Determination Of The Activation Energy E And Frequency Factor A Reaction Table 5 Temp Of Time Temp Relative 2
Part B Determination Of The Activation Energy E And Frequency Factor A Reaction Table 5 Temp Of Time Temp Relative 2 (62.4 KiB) Viewed 113 times
Part B Determination Of The Activation Energy E And Frequency Factor A Reaction Table 5 Temp Of Time Temp Relative 3
Part B Determination Of The Activation Energy E And Frequency Factor A Reaction Table 5 Temp Of Time Temp Relative 3 (32.86 KiB) Viewed 113 times
Part B Determination Of The Activation Energy E And Frequency Factor A Reaction Table 5 Temp Of Time Temp Relative 4
Part B Determination Of The Activation Energy E And Frequency Factor A Reaction Table 5 Temp Of Time Temp Relative 4 (30.69 KiB) Viewed 113 times
Part B: Determination of the Activation Energy (E.) and Frequency factor (A) Reaction Table 5 Temp of Time Temp Relative rate 1000/t reaction (K) mixture Avg, time (s) oc "From parta 72.5 5 (+ 7259 = 295k 22°C | 22°C + 275K 1000 13.79 500 1000 054 7.50 Wed 2.47 104.66 278K cro 1. 06824:57 2. 7:18 3. 6:30 Avg. time (s) 404.66 1. N25 100 2. 1:27 3.799 1439 Avg. time (s) 100.66 2100 °C 7+ 53.0 322 +49 1213 =9.93 1000 100.66 520 31,20 30°C 303k 40°C 2. 1:19 047 1. N:25 se 87.00% 372 3. 177083 1000 =20.0 SO OSO 3 otac 3be 313K °C Avg. time (5) 50.00s 1. 2. 3. Avg. time (5) Use the following equation to calculate the activation energy (E.) k = Ae-Ea/RT Taking the logarithm, we get: Ink = -1 + InA RT 71

Table 6: k at each Temperature: from rate law determined in part A, Complete the following table for the four temperatures. Show calculations with correct units. Reaction T (K) 1/T (K Temperature(°C) 1) k Ink 3.799 22 295k 10003년 2.47 247 5 278 Rate = PEP JCB0, JGHT 295 13.70 [(002)(008)(02)² - /21.49) 2.155.10.9 -0036 1-4.617 160048) 1.008) (-02)² = 00988 303 1.00336 (.002)(011).cz)? 7.76-108 1.0032k 20.0 C.002)600)6.04) 9.9.3 120.47 9.93 30 40 120.48 313 20.0 7.81.102 Using Excel 1. Plot a scatter graph of "Ink versus 1/T". Be sure to label the axis and title your graph. 2. Fit a trend line to your plotted data, and obtain both the equation of the trend line and the R2 value. 3. Submit a printout of this graph along with the complete data table with your datasheets & calculations. 4. Calculate and report the activation energy, E, and the frequency factor, A, for this reaction (include units!). Show complete calculations for determining Ea and A. 72

1. Plot a scatter gra 2. Fit a trend line to y the R value. Submit a printout of datasheets & calculatio Using Excel 70.0 late and report the acti on (include units!). Show Toon C.002] 11 203-2² wher' Equation of the line: R? (Correlation coefficient) Calculations of E.: 0/mol) K-He-E/RT lak e hind 7 E. (kl/mol) Calculations of A (frequency Factor) A (frequency factor): Part C. Effect of a Catalyst upon Reaction Rate Table 7: Reaction mixture 1 Time (s) Te K *From part A. reaction mixture 1 k T K Plus catalyst By what factor did the rate of reaction increase? kome/uscate 73

Results: Rate Law Rate Constant Activation Energy Frequency Factor kcatalysed/kuncatalysed
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