8. (20 points) Silver (I) has a reduction potential of 0.799 V. If the solubility product of Ag2S is 6.0 x 1051 (Ksp=[Ag

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answerhappygod
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8. (20 points) Silver (I) has a reduction potential of 0.799 V. If the solubility product of Ag2S is 6.0 x 1051 (Ksp=[Ag

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8 20 Points Silver I Has A Reduction Potential Of 0 799 V If The Solubility Product Of Ag2s Is 6 0 X 1051 Ksp Ag 1
8 20 Points Silver I Has A Reduction Potential Of 0 799 V If The Solubility Product Of Ag2s Is 6 0 X 1051 Ksp Ag 1 (99.46 KiB) Viewed 95 times
8. (20 points) Silver (I) has a reduction potential of 0.799 V. If the solubility product of Ag2S is 6.0 x 1051 (Ksp=[Ag+7°[S?]) and the pKa H2S is 7.05 and the pKa of HS is 19. Estimate the reduction potential for the following reaction using the data provided above. Assume 25°C (Do not look up the results on the internet. You must show your calculation using the above information). a. Ag2S(s)+H7+2e 2Ag(s)+HS b. Write the appropriate Nernst equation for this half-cell. c. A Silver/Silver Sulfide electrode is used with calomel reference electrode with a half-cell voltage of 0.244 V. If the high impedance meter reads -443 mV at a pH of 7.2 what is the concentration of H2S, HS and S-??
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