Mass of aluminum used 0.9979 Moles of alumnium used 0.03699 Theorical yield 17.55 g Yield of Alum crude grams

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Mass of aluminum used 0.9979
Moles of alumnium used 0.03699
Theorical yield 17.55
g
Yield of Alum crude grams 9.4314g
Percent yiel__________?
Final REACTION
2Al(s)+ 2KOH(aq) +4H2SO4(aq) + → 2KAl(SO4)2•12H2O(s)
WEIGHT Recrystallized yield of Alum---6.5202 gr
1. Does the yield you obtained in this lab support using
the procedure to efficiently recycle aluminum? Explain why or why
not and how the process might be made more
efficient.
2. Describe your efforts to recrystallize Alum. Did you
grow a single crystal? Why or why not? Calculate your percent
recovery from the recrystallization.
%Recovery = Recrystallized yield of Alum (grams)Yield of
crude Alum (grams) x 100
%Recovery =
3. The formula of the mineral alunite is
KAl3(SO4)2(OH)6. What mass of aluminum is in 1.00 kg of the mineral
alunite?