R = 0.008315 kJ/molók F = 96.48 kJ/v•K 1. (10 pts) A cell must import Cu2+ for proteins that are involved in oxidative p

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R = 0.008315 kJ/molók F = 96.48 kJ/v•K 1. (10 pts) A cell must import Cu2+ for proteins that are involved in oxidative p

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R 0 008315 Kj Molok F 96 48 Kj V K 1 10 Pts A Cell Must Import Cu2 For Proteins That Are Involved In Oxidative P 1
R 0 008315 Kj Molok F 96 48 Kj V K 1 10 Pts A Cell Must Import Cu2 For Proteins That Are Involved In Oxidative P 1 (48.03 KiB) Viewed 42 times
R = 0.008315 kJ/molók F = 96.48 kJ/v•K 1. (10 pts) A cell must import Cu2+ for proteins that are involved in oxidative phosphorylation. Consider a cell at 37°C with a transmembrane potential of 70 mV (inside negative), where the Cu2+ concentration outside the cell is 0.02 uM and 0.15 um inside the cell. a. Write the expression that is used to calculate the free energy of transport for charged solutes. a b. Substitute the appropriate values from the situation described above to calculate the free energy of transport for Cut into the cell. You do NOT need to solve the equation. c. Which term(s) in the expression for free energy of transport are energetically favorable in the situation described above? brabro borib The concentration term The electrochemical term Both terms Neither term
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