Combustion data allows us to solve for the empirical formula. Although the goal is often the smallest whole number ratio

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Combustion Data Allows Us To Solve For The Empirical Formula Although The Goal Is Often The Smallest Whole Number Ratio 1 (70.08 KiB) Viewed 69 times

Combustion Data Allows Us To Solve For The Empirical Formula Although The Goal Is Often The Smallest Whole Number Ratio 2 (48.34 KiB) Viewed 69 times

Combustion Data Allows Us To Solve For The Empirical Formula Although The Goal Is Often The Smallest Whole Number Ratio 3 (53.63 KiB) Viewed 69 times

Combustion Data Allows Us To Solve For The Empirical Formula Although The Goal Is Often The Smallest Whole Number Ratio 4 (53.63 KiB) Viewed 69 times

Combustion data allows us to solve for the empirical formula. Although the goal is often the smallest whole number ratio, we will take a different approach so that we do not work in the wrong direction. Make sure to consider oxygen and use masses from the periodic table to only two decimal places. Divide by the smallest number of moles and you should get the relative moles of each element. Report these as whole numbers (such as CH ) if applicable but for now, it is okay to report these as decimals (such as C, HO). Once we learn the molecular mass of the unknown, we will be able to convert our data into molecular formulas. 125 Combustion problems for IR/MS assignment Temporarily skip problems shaded. Complete answers on back grid. You will add the answers to the skipped problems when we cover spectroscopy. #1: A 105.39 mg sample of unknown was submitted for combustion analysis. The sample yielded 330.60 mg of carbon dioxide and 135.37 mg of water #2: A 574.98 mg sample of unknown was submitted for combustion analysis. The sample yielded 1694.39 mg of carbon dioxide and 504.56 mg of water. #3: A 132,17 mg sample of unknown was submitted for combustion analysis. The sample yielded 220.05 mg of carbon dioxide and 72.08 mg of water. #4: A 30.05 mg sample of unknown was submitted for combustion analysis. The sample yielded 99.02 mg of carbon dioxide and 27.03 mg of water. #5: A 52.29 mg sample of unknown was submitted for combustion analysis. The sample yielded 127.63 mg of carbon dioxide and 52.26 mg of water. #6: A 74.07 mg sample of unknown was submitted for combustion analysis. The sample yielded 159.54 mg of carbon dioxide and 65.32 mg of water.

#7: A 585.68 mg sample of unknown was submitted for combustion analysis. The sample yielded 1800 mg of carbon dioxide and 842.8 mg of water #8: A 46,30 mg sample of unknown was submitted for combustion analysis. The sample yielded 115.53 mg of carbon dioxide and 56.76 mg of water 19:This unknown contains 51 90% and 9.80% Il by mass with the remainder being an unknown element (you have to figure out what clement) mo: This unknown contains 60.96%. Cand 15.35 H by mass with the remainder being an unknown element (you have to figure out what element) #11: A 150.26 mg sample of unknown was submitted for combustion analysis. The sample yielded 495.11 mg of carbon dioxide and 133.15 mg of water. #12: A 423.25 mg sample of unknown was submitted for combustion analysis. The sample yielded 1001.23 mg of carbon dioxide and 409.96 mg of water. #13: A 178.50 mg sample of unknown was submitted for combustion analysis. The sample yielded 576,53 mg of carbon dioxide and 188.85 mg of water #14: A 156.32 mg sample of unknown was submitted for combustion analysis. The sample yielded 336.68 mg of carbon dioxide and 137.85 mg of water #15: This unknown contains 65.69% and 15,16% H by mass with the remainder being an unknown clement (you have to figure out what element) #16: This unknown contains 28.77% C.4.22% H and 19.16% Oxygen by mass with the remainder being an unknown element (you have to figure out what clement), #17: A77.86 mg sample of unknown was submitted for combustion analysis. The sample yielded 184.84 mg of carbon dioxide and 94.61 mg of water. #18: This unknown contains 68.90% and 15.03% H by mass with the remainder being an unknown clement (you have to figure out what element). #19: A 239.86 mg sample of unknown was submitted for combustion analysis. The sample yielded 646.95 mg of carbon dioxide and 264.89 mg of water #20: A 286,52 mg sample of unknown was submitted for combustion analysis. The sample yielded 605.14 mg of carbon dioxide and 297.33 mg of water.

Combustion problems for IR/MS assignment Temporarily skip problems shaded. Complete answers on back grid. You will add the answers to the skipped problems when we cover spectroscopy. #1: A 105.39 mg sample of unknown was submitted for combustion analysis. The sample yielded 330.60 mg of carbon dioxide and 135.37 mg of water. #2: A 574.98 mg sample of unknown was submitted for combustion analysis. The sample yielded 1694.39 mg of carbon dioxide and 504.56 mg of water. #3: A 132.17 mg sample of unknown was submitted for combustion analysis. The sample yielded 220.05 mg of carbon dioxide and 72.08 mg of water. #4: A 30,05 mg sample of unknown was submitted for combustion analysis. The sample yielded 99.02 mg of carbon dioxide and 27.03 mg of water. #5: A 52.29 mg sample of unknown was submitted for combustion analysis. The sample yielded 127.63 mg of carbon dioxide and 52.26 mg of water. #6: A 74.07 mg sample of unknown was submitted for combustion analysis. The sample yielded 159.54 mg of carbon dioxide and 65.32 mg of water.