Question 14 5 pts When 2-methylpent-2-ene is reacted with BHz followed by H2O2/OH', the major product obtained will be H

Post by **answerhappygod** » Tue May 17, 2022 8:11 am

: Question 14 5 Pts When 2 Methylpent 2 Ene Is Reacted With Bhz Followed By H2o2 Oh The Major Product Obtained Will Be H 1 (39.84 KiB) Viewed 76 times

: Question 14 5 Pts When 2 Methylpent 2 Ene Is Reacted With Bhz Followed By H2o2 Oh The Major Product Obtained Will Be H 2 (48.31 KiB) Viewed 76 times

: Question 14 5 Pts When 2 Methylpent 2 Ene Is Reacted With Bhz Followed By H2o2 Oh The Major Product Obtained Will Be H 3 (50.09 KiB) Viewed 76 times

Question 14 5 pts When 2-methylpent-2-ene is reacted with BHz followed by H2O2/OH', the major product obtained will be HOCH2CH(CH3)CH2CH2CH3 O (CH3)2C(OH)CH2CH2CH3 (CH3)2CHCH(OH)CH2CH3 (CH3)2CHCH2CH(OH)CH3

Question 17 5 pts How will you convert 2-propanol, CH3CH(OH)CH3 to 1-propanol. (CH3CH2CH2OH) ? 1) KOC(CH3)3 2) Hg(OAc)2, H2O followed by NaBHA/OH 1) H2SO4, heat 2) BH, followed by H2O/OH 1) H2SO4, heat 2) Hg(OAc)2, H20 followed by NaBH /OH 1) KOC(CH3)3 2) H2O/H* 1) KOC(CH3)3 2) BH, followed by H202/OH" D Question 18

Question 20 5 pts When 1-methylcyclohexene is treated with BH3.THF followed by H2O2/OH", it leads to: O addition of water according to Markovnikov's rule (Anti Addition of water) addition of water according to Anti-Markovnikov's rule (Syn Addition of water) addition of water according to Anti-Markovnikov's rule (Anti Addition of water) addition of water according to Markovnikov's rule (Syn Addition of water) Question 21