(a) 25.0 cm3 of potassium hydroxide, concentration 2.53 mol/dm3, was neutralised by 28.2 cm3 of dilute sulfuric acid. 2K

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answerhappygod
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(a) 25.0 cm3 of potassium hydroxide, concentration 2.53 mol/dm3, was neutralised by 28.2 cm3 of dilute sulfuric acid. 2K

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A 25 0 Cm3 Of Potassium Hydroxide Concentration 2 53 Mol Dm3 Was Neutralised By 28 2 Cm3 Of Dilute Sulfuric Acid 2k 1
A 25 0 Cm3 Of Potassium Hydroxide Concentration 2 53 Mol Dm3 Was Neutralised By 28 2 Cm3 Of Dilute Sulfuric Acid 2k 1 (37.71 KiB) Viewed 334 times
(a) 25.0 cm3 of potassium hydroxide, concentration 2.53 mol/dm3, was neutralised by 28.2 cm3 of dilute sulfuric acid. 2KOH(aq) + H2SO4(aq) → K2SO4(aq) + 2H2O(1) Calculate the concentration of the sulfuric acid. number of moles of KOH used = number of moles of H2SO4 needed to neutralise the KOH = I concentration of dilute sulfuric acid = mol/dm3 13
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