Shown Below Is The Philips Condensation Of 4 Methylbenzene 1 2 Diamine And Pentanoic Acid The Amounts Of Each Starting 1 (37.47 KiB) Viewed 48 times
Shown Below Is The Philips Condensation Of 4 Methylbenzene 1 2 Diamine And Pentanoic Acid The Amounts Of Each Starting 2 (37.47 KiB) Viewed 48 times
Shown Below Is The Philips Condensation Of 4 Methylbenzene 1 2 Diamine And Pentanoic Acid The Amounts Of Each Starting 3 (37.47 KiB) Viewed 48 times
Shown below is the Philips condensation of 4-methylbenzene-1,2-diamine and pentanoic acid. The amounts of each starting material used in the reaction are given. Also, the amount of product obtained from the reaction is indicated Please use the space below to answer the following three questions ( you can also answer all three questions together and attach one file with your answers on it) below. a) Draw the structure of intermediate A b) Draw a mechanism for the conversion of 4-methylbenzene-1,2-diamine and pentanoic acid to intermediate A. C) Draw a mechanism for the conversion intermediate A to the final product. NH2 Intermediate A + H20 HO NH2 pentanoic acid 4-methylbenzene- 1,2-diamine 5-methyl-2-butyl-1H- benzlomidazole CHIN, Molecular Weight: 188.27 C,H,O, Molecular Weight: 102.13 dentity 093ml CHIN Molecular Weight: 122.17 1.50 grams 1.00 mL 1.12 grams A F !!! B 1 US X: Learn Video
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