- 12 Compound B Has A Molecular Formula C6h10 And Gives Ch3 2chch2ch2ch3 Shown Below When Treated With Excess H2 In 1 (62.58 KiB) Viewed 111 times
12. Compound B has a molecular formula, C6H10, and gives (CH3)2CHCH2CH2CH3 (shown below) when treated with EXCESS H2 in
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12. Compound B has a molecular formula, C6H10, and gives (CH3)2CHCH2CH2CH3 (shown below) when treated with EXCESS H2 in
12. Compound B has a molecular formula, C6H10, and gives (CH3)2CHCH2CH2CH3 (shown below) when treated with EXCESS H2 in the presence of a Pd catalyst. B reacts with NaNH2 and CH3l to form compound C (molecular formula, C7H12). Answer the questions below: (16 pts) Compound B molecular formula = CH 10 1. NaNH2 2. CH,Br Compound C molecular formula = CH₂2 Excess H,, Pd (CH3)2CHCH2CH2CH3 Calculate the degrees of unsaturation for Compound C (3 pts) 12.1 12.2 Calculate the degrees of unsaturation for Compound B (3 pts) 12.3 12.4 Write the chemical structure of Compound B (5 pts) Write the chemical structure of Compound C (5 pts)
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