25.0 mL of 0.375 M NaH2PO4(aq) solution is titrated with 0.375 M KOH(aq) solution. What is the pH of the resulting solut

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answerhappygod
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25.0 mL of 0.375 M NaH2PO4(aq) solution is titrated with 0.375 M KOH(aq) solution. What is the pH of the resulting solut

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25.0 mL of 0.375 M NaH2PO4(aq) solution is titrated with 0.375 M
KOH(aq) solution. What is the pH of the resulting solution at the
equivalence point? For H2PO4– (aq), Ka = 6.2 x 10–8. The titration
reaction is: H2PO4– (aq) + KOH(aq) → HPO42– (aq) + H2O(l)
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