One industrial path for the production of ammonia follows: Ca(OH)2 + 2NH4Cl +CaCl2 + 2 H2O + 2NH3 If 40.586g of Ca(OH)2

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One industrial path for the production of ammonia follows: Ca(OH)2 + 2NH4Cl +CaCl2 + 2 H2O + 2NH3 If 40.586g of Ca(OH)2

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One Industrial Path For The Production Of Ammonia Follows Ca Oh 2 2nh4cl Cacl2 2 H2o 2nh3 If 40 586g Of Ca Oh 2 1
One Industrial Path For The Production Of Ammonia Follows Ca Oh 2 2nh4cl Cacl2 2 H2o 2nh3 If 40 586g Of Ca Oh 2 1 (18.89 KiB) Viewed 45 times
One industrial path for the production of ammonia follows: Ca(OH)2 + 2NH4Cl +CaCl2 + 2 H2O + 2NH3 If 40.586g of Ca(OH)2 and 40.586g of NH4Cl are mixed, how many grams of EXCESS reactant are left? Your answer should be numerical and neglect units (e.g., if you calculate 3.5g then input 3.5).
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