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How do we calculate the consetration c in the tabel via this formula:
תן - Sodium hydroxide (NaOH) p=cv Mw (0,04mol.dm-3)(1dm) m 39,997g.mol-11 Thus: m = 1,6g -NaOH with 1dm" water. ན། Ethyl acetate -3 p=902kg.m 0,902g.ml-11 n=cV = (0,04mol.dm-3) (0,5dm3) = 0,02moll т = пM (0,02mol)(88,11g.mol-1) = 1,762291 - 772 V = P 1,76229 0,902g.m-3 1,95ml-ethyl acetate that is filled up with water up to 500ml. पा - Hydrochloric acid (HCI) 1 p 1,189.ml-1 0,032mol.ml-1 = 32 mol.1-19 M 36,458g.mol-1 Then: (32mol. 1-1)(32%) = 10,24mol. dm-31 Thus:- CV. = C2V21 (0,04mol. dm-3)(100ml) = (10,24mol. dm-3)V21 V2 = 0,39ml HCl and the water filled to 100ml.
3 1/c (dm3 mol-1] c[mol T [min] Tt/cm dm) 5 21,2 10 22,5 15 23 20 23 25 23 30 24,3
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Calculations Table How do we calculate the consetration c in the tabel via this formula:
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Calculations Table How do we calculate the consetration c in the tabel via this formula:
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