Acousing Voe colour DOSA HV Adjust Current Ads Dan Figure 2 Figure 3 shows a simplified schematic of an electron gun. A

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Acousing Voe Colour Dosa Hv Adjust Current Ads Dan Figure 2 Figure 3 Shows A Simplified Schematic Of An Electron Gun A 1 (120.77 KiB) Viewed 54 times

Acousing Voe colour DOSA HV Adjust Current Ads Dan Figure 2 Figure 3 shows a simplified schematic of an electron gun. A relatively low voltage battery, with electromotive force AV, drives a current through a filament. Due to the natural resistance of the filament, the current causes the filament to heat up. The high temperature causes electrons to fly off the filament. Initially, these electrons have low speeds. A relatively high voltage battery, with electromotive force AV2, creates an electric field that accelerates the electrons. The high voltage battery is connected to two conductors, labeled as anode and cathode in Figure 3. The two conductors act much like a parallel-plate capacitor. The field between these plates is responsible for accelerating the electrons. A small hole at the center of each plate allows electrons to pass through. Let us calculate the speed of a typical electron as it is accelerated from the cathode to the anode. Suppose the electron's initial speed is zero, which implies: 132 Ky = mv} = 0 Also suppose that potential at the cathode is zero, which implies: Ui = qVi = 0 The potential at the anode must be higher than the cathode, because the anode is connected to the positive terminal of the battery. If potential at the cathode is zero, then potential at the anode must be AV2, which implies: Ug = qV; = 24V2 Using conservation of energy, calculate the final speed of the electron in terms of m,q and AV2: [Equation 5]