A radioactive sample of Iridum-179 (atomic number: 77) undergoes the the following decay processes in the following orde

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answerhappygod
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A radioactive sample of Iridum-179 (atomic number: 77) undergoes the the following decay processes in the following orde

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A radioactive sample of Iridum-179 (atomic number: 77) undergoes
the the following decay processes in the following order: Alpha
decay, Beta + decay, Beta + decay, Gamma Decay, Alpha decay and
Beta - decay. Which of the following would be the resultant
nuclide after all decay processes have finished? Please provide
explanation of answer.
Osmium-191 (atomic number: 76)
Gold-192 (atomic number: 79)
Tungsten-179 (atomic number: 74) ****
Halfium-189 (atomic number: 72)
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