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2 x 106 ۱۱ 2 Q1. Calculate the mass of the Earth. Use, G = 6.67408 x 10-11 m’kg 's-2; Radius of the Earth = 6371 km, and gravity, g = 9.8 m/s g= Gm /r2 g=6.67 x 10-11 xM/63718 M=9.8 X 63712 1 6.67x10-11 IM=5.96369 x 1024 Q2. The Earth is not quite round--the radius at the pole is 6357 km and 6378 km at the equator, Calculate the acceleration due to the gravity on both equator and poles. 98 tm I requator Gravity a pole: g=om Ir poles 6.67x10-11 85.9637X 1024 63572 x 106 9.8432 m/s² ga poles Gravity & equator : 6.67x10-1 x 5.9637x1024 = 9.778 m/s² 6378² x 106 (a) Where on the surface of the Earth would you weigh the most? The poles - given more gravity to weigh you down (b) Where on the surface of the Earth would you weigh the least? The equator- the product of mass & gravity is less Gravity (20 POINTS) In your in-class assignment, you computed the difference in gravity expected at the equator compared to the poles (10 POINTS). 1. What are the three main factors responsible for different gravity values at the equator and poles? m 2. Draw sketches and explain (using the equations) how each of these factors contributes to the theoretical gravity value computed at various latitudes.