Attempt: 1 2 UNTUN Distance from Table to Landing 0.50 m 0.53 m 0.56 m 0.52 m 10.50 m 6. Now let's take a theoretical

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answerhappygod
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Attempt: 1 2 UNTUN Distance from Table to Landing 0.50 m 0.53 m 0.56 m 0.52 m 10.50 m 6. Now let's take a theoretical

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Attempt 1 2 Untun Distance From Table To Landing 0 50 M 0 53 M 0 56 M 0 52 M 10 50 M 6 Now Let S Take A Theoretical 1
Attempt 1 2 Untun Distance From Table To Landing 0 50 M 0 53 M 0 56 M 0 52 M 10 50 M 6 Now Let S Take A Theoretical 1 (35.89 KiB) Viewed 27 times
Attempt 1 2 Untun Distance From Table To Landing 0 50 M 0 53 M 0 56 M 0 52 M 10 50 M 6 Now Let S Take A Theoretical 2
Attempt 1 2 Untun Distance From Table To Landing 0 50 M 0 53 M 0 56 M 0 52 M 10 50 M 6 Now Let S Take A Theoretical 2 (34.61 KiB) Viewed 27 times
Attempt: 1 2 UNTUN Distance from Table to Landing 0.50 m 0.53 m 0.56 m 0.52 m 10.50 m

6. Now let's take a theoretical approach to the distance travelled. If we want to calculate the expected distance from the table, we need to know the velocity of the ball as it leaves the table. Using the height of the table, estimate the time of flight of the ball. You may find that the equation Ay = Voy +(42)*g*t*, where Ay is the height of the table, Voy is zero, as the ball is moving horizontally, and you want to solve fort. Write your working and the answer below: Height of table= 0.914 m
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