m = 4. Two particles, each of mass m=0.85 kg, are fastened to each other by two rods, each with length d = 5.6 cm and ma

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answerhappygod
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m = 4. Two particles, each of mass m=0.85 kg, are fastened to each other by two rods, each with length d = 5.6 cm and ma

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M 4 Two Particles Each Of Mass M 0 85 Kg Are Fastened To Each Other By Two Rods Each With Length D 5 6 Cm And Ma 1
M 4 Two Particles Each Of Mass M 0 85 Kg Are Fastened To Each Other By Two Rods Each With Length D 5 6 Cm And Ma 1 (30.97 KiB) Viewed 56 times
m = 4. Two particles, each of mass m=0.85 kg, are fastened to each other by two rods, each with length d = 5.6 cm and mass M=1.2 kg. The combination as shown in Fig. 2, rotates around the rotation axis through point O, with angular speed o = 0.30 rad/s. For a long thin rod (axis through center of mass) moment of inertia Icom = Md. 12 m M Rotation axis Fig. 2 (a) Find the rotational inertia of the rotating system. (b) What is the kinetic energy of the system? (c) Calculate the magnitude of the angular momentum of the system. (6) (2) (2)
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