Figure 01 shows the L m long overhanging simply supported beam ABC is subjected to triangular load of 6 kN/m, uniformly
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Figure 01 shows the L m long overhanging simply supported beam ABC is subjected to triangular load of 6 kN/m, uniformly
Figure 01 shows the L m long overhanging simply supported beam ABC is subjected to triangular load of 6 kN/m, uniformly distributed load of 4 kN/m and point load of 7.5 kN. There is an anti-clockwise moment of 10 kNm at support A ALL loadings for the beam ARE CONSTANT for all groups as indicated in Figure 01. However, the length of the beam. L varies depending on group number as shown in Table 1. 7.5 KN 6 kN/m 4 kN/m 10 kNm L/3 m L13 m U6 m U6 m Figure Q1: Overhanging beam, ABC 2 Table 1 Length of the beam, L Group Length (m) 1 6 2 7 8 TI 4 9 5 10 11 6 7 12 a) Derive the shear formula of the overhanging beam, then use bracketing or open method find the point where the shear equals zero (7 marks) b) Select the stopping criterion and justify the accuracy and precision of the result in (a) [3 marks)
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