Two horizontal forces P= 20 kN are applied to pin B of the assembly shown in the figure blew, Knowing that a pin of 16 m

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Two Horizontal Forces P 20 Kn Are Applied To Pin B Of The Assembly Shown In The Figure Blew Knowing That A Pin Of 16 M 1 (216.65 KiB) Viewed 46 times

Two Horizontal Forces P 20 Kn Are Applied To Pin B Of The Assembly Shown In The Figure Blew Knowing That A Pin Of 16 M 2 (27.94 KiB) Viewed 46 times

Two Horizontal Forces P 20 Kn Are Applied To Pin B Of The Assembly Shown In The Figure Blew Knowing That A Pin Of 16 M 3 (30.02 KiB) Viewed 46 times

Two horizontal forces P= 20 kN are applied to pin B of the assembly shown in the figure blew, Knowing that a pin of 16 mm diameter is used at each connection. 10 mm B 50 mm PKN PKN 10 mm 45° А 50 mm 70°
a) Determine the member force. Please insert - sign if it indicates the compressive member. FAB = KN FBC = KN b) Determine the maximum value of the average normal stresses in link AB and in link BC. Please insert - sign if it indicates the compressive stress. OAB Ав MPa Овс MPа
c) Determine the average shearing stresses in the pin at A, B, and C; TA = MPа TB = MPа Tc = MPa d) Determine the average bearing stresses at Ain member AB, at Bin member BC, and at Cin member BC. Bearing Stress A = MPа Bearing Stress B= MPa Bearing Stress C = MPa