MB 2 TEST 2: SPLITTING TENSION TEST (BS EN 12390-6: 2009) Table 2. Result of Splitting Tension Test Cylinder Specimen Number Age(Day) Diameter,d (mm) Height, L (mm) Failure Load, F (kN) Tensile strength, fet (MPa) Average Tensile Strength (MPa) Si 28 100.00 201.00 135.10 4.28 S2 28 102.50 199.00 107.40 3.35 3.73 S3 28 105.00 200.00 117.50 3.56 Formula: F = ct 2xF TxLxd Where Fo= Tensile splitting strength (MPa or N/mm²) F = Maximum load (N) L = Length of the line of contact of the specimen (mm) =
d Designated cross-sectional dimension (mm) 2 x 135.10 x103 Specimen 1: Fct Tx 201.00 x 100.00 = 4.28 MPa 2 x 107.40 x103 Specimen 2: Fct 1 x 199.00 x 102.50 = 3.35 MPa 2 x 117.50 x103 Specimen 3: Fct n x 200.00 x 105.00 = 3.56MPa Average tensile strength 4.28 +3.35+3.56 3 = 3.73 MPa
Based on the result obtained above, explain in detail the effect of curing on the development of compressive strength.
MB 2 TEST 2: SPLITTING TENSION TEST (BS EN 12390-6: 2009) Table 2. Result of Splitting Tension Test Cylinder Specimen Nu
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MB 2 TEST 2: SPLITTING TENSION TEST (BS EN 12390-6: 2009) Table 2. Result of Splitting Tension Test Cylinder Specimen Nu
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