A cam is to be used for a platform that will repeatedly lift boxes from a lower conveyor to an upper conveyor as shown i

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899604
Joined: Mon Aug 02, 2021 8:13 am

A cam is to be used for a platform that will repeatedly lift boxes from a lower conveyor to an upper conveyor as shown i

Post by answerhappygod »

A Cam Is To Be Used For A Platform That Will Repeatedly Lift Boxes From A Lower Conveyor To An Upper Conveyor As Shown I 1
A Cam Is To Be Used For A Platform That Will Repeatedly Lift Boxes From A Lower Conveyor To An Upper Conveyor As Shown I 1 (108.55 KiB) Viewed 36 times
solve it 100%
A cam is to be used for a platform that will repeatedly lift boxes from a lower conveyor to an upper conveyor as shown in the Figure below. It will go through the following motion sequence in one revolution of the cam: rise 4 inch in 2 second, dwell for 1 second, fall 2 inch in 1 second, dwell for 1 second, fall 2 inch in 1 second. BOU A box lifiting mechanism 1) What is the time of a full cycle? (5 point) What motion sequence it is in when the cam rotated cycle? (5 point) 2) What is the angular velocity of the cam (with units)? (5 points) 3) Plot the s diagram. Use cam angle (degree) as the x-axis and the displacement (inch) as the y-axis. For rise and fall, as the function is not given, just mark the start and end points. (15 points) 4) Assuming the design satisfies the fundamental law of cam design, list the boundary conditions (s,v,a) for the rise function. (5 points) 5) List the boundary conditions (s,v,a) for the first fall function. (5 points)
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply