Link 2 30 Aus = a, xr + 502 xły xr 3 ?? plate weight = 490 16/ff3 = .0354 16/ft² | plate thickness - 1/8" I just need F

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answerhappygod
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Link 2 30 Aus = a, xr + 502 xły xr 3 ?? plate weight = 490 16/ff3 = .0354 16/ft² | plate thickness - 1/8" I just need F

Post by answerhappygod »

Link 2 30 Aus A Xr 502 Xly Xr 3 Plate Weight 490 16 Ff3 0354 16 Ft Plate Thickness 1 8 I Just Need F 1
Link 2 30 Aus A Xr 502 Xly Xr 3 Plate Weight 490 16 Ff3 0354 16 Ft Plate Thickness 1 8 I Just Need F 1 (44.46 KiB) Viewed 38 times
example:
Link 2 30 Aus A Xr 502 Xly Xr 3 Plate Weight 490 16 Ff3 0354 16 Ft Plate Thickness 1 8 I Just Need F 2
Link 2 30 Aus A Xr 502 Xly Xr 3 Plate Weight 490 16 Ff3 0354 16 Ft Plate Thickness 1 8 I Just Need F 2 (61.96 KiB) Viewed 38 times
yes. i need it to find acceleration about the CG(center of gravity)
(center of gravity)
Link 2 30 Aus = a, xr + 502 xły xr 3 ?? plate weight = 490 16/ff3 = .0354 16/ft² | plate thickness - 1/8" I just need F value
Biloxi Lafayette Houston (228) 435-5000 (337) 988-2302 (800) 245-8275 SCALE: Linie z accell () 2 G -707(2,127+.5) 1.85" 5707/4,5) 1.146 2.121 1.85 2.121" Aaz = Ver tw xwxr TG2 = -10,4610 x 10,ARX 1.146 +1.851 ãoz = -125,47- 202.45 O2) L LINK 2
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