d=L/2 Q6. The slender rod shown in the picture has mass M = 6 kg and length L = 3 m, and moment of Inertia = ML°/12. Thi

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D L 2 Q6 The Slender Rod Shown In The Picture Has Mass M 6 Kg And Length L 3 M And Moment Of Inertia Ml 12 Thi 1 (33.5 KiB) Viewed 29 times

d=L/2 Q6. The slender rod shown in the picture has mass M = 6 kg and length L = 3 m, and moment of Inertia = ML°/12. This rod is at rest but free to rotate around fixed point B. A small ball of negligible radius and mass M = 1 kg hits the rod at mid-length of d = 4/2 with velocity of 1.5 m/s. Part a) If the ball sticks to the rod after impact, what will be the angular velocity of the "rod+ball system" immediately after impact. Select the conservation law you can use to solve this problem: Conservation of energy Conservation of linear momentum Conservation of angular momentum W = Part b) How much energy is lost during this impact? Energy Lost =