W = (1 kw)(1 hour) W= 1kWh- 3.6X100T Kilowatthour Chr. 8 ) HW Imke volume: Oom 200m x 1,500 m 1 density of Water = 1000

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answerhappygod
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W = (1 kw)(1 hour) W= 1kWh- 3.6X100T Kilowatthour Chr. 8 ) HW Imke volume: Oom 200m x 1,500 m 1 density of Water = 1000

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W 1 Kw 1 Hour W 1kwh 3 6x100t Kilowatthour Chr 8 Hw Imke Volume Oom 200m X 1 500 M 1 Density Of Water 1000 1
W 1 Kw 1 Hour W 1kwh 3 6x100t Kilowatthour Chr 8 Hw Imke Volume Oom 200m X 1 500 M 1 Density Of Water 1000 1 (46.03 KiB) Viewed 58 times
W = (1 kw)(1 hour) W= 1kWh- 3.6X100T Kilowatthour Chr. 8 ) HW Imke volume: Oom 200m x 1,500 m 1 density of Water = 1000 kg/m² h h= 500m b a (i) calculate PE in J and in kWh (ii) if (*) = 2x 104 mg/s find the power output (iii) calculate the time to drain 7 the lake.
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