Shown is a shaft mounted in bearings at A and D and having pulleys at B and C. The forces shown on the pulley surfaces r

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Shown is a shaft mounted in bearings at A and D and having pulleys at B and C. The forces shown on the pulley surfaces r

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Shown Is A Shaft Mounted In Bearings At A And D And Having Pulleys At B And C The Forces Shown On The Pulley Surfaces R 1
Shown Is A Shaft Mounted In Bearings At A And D And Having Pulleys At B And C The Forces Shown On The Pulley Surfaces R 1 (55.51 KiB) Viewed 41 times
Shown is a shaft mounted in bearings at A and D and having pulleys at B and C. The forces shown on the pulley surfaces represent the belt tensions. 6-in D. 300 lbf 50 lbf 27 lbf 360 lbf D C.6 in 8-in D. 8 in B 8 in Static force analysis yields the following results for the bearing reactions in xy and xz planes. xy plane xz plane = 127 lbf 387 lbf سم لها = 223 lbf B 8" 8" 6" A D 8" B с FA = 106 lbf 350 lbf FD, = 281 lbf
Design Constraint Bearings at A and D being spherical ball bearings and referring to Table ci 7-2 from Shigley's Mechanical Engineering Design Book, the slope magnitude at the bearings should not exceed 0.052 radian. Design Constraint The magnitude of transverse deflection at a pulley's location on the C2 shaft should not exceed 0.02 in. 2.d. Check whether constraints C1 and C2 are satisfied. If constraints C1 and C2 are not both satisfied, then you will be required to find a new adequate diameter for the shaft as explained below. • If the allowable deflection is exceeded, since I is proportional to dt, a new diameter can be found from: Sold dnew = dold 18 allowable If the allowable slope is exceeded, a new diameter can be found from: . Bold dnew = dold Pallowable In case several corrections are applicable, take the diameter with the largest dnew/dold ratio. 2.e. If applicable, determine the new shaft diameter and recalculate the total slopes at the bearings and the total deflections at the pulleys accordingly.
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