A 6 m by 10 m solar array installed on a flat horizontal surface in Birmingham produces 12000 W of power on Day Number 1

[answerhappygod]

A 6 m by 10 m solar array installed on
a flat horizontal surface in Birmingham produces 12000 W of power
on Day Number 130. Assuming clear sky conditions under AM1.5 and
using relevant equations in the APPENDIX,
calculate:
(i) The
sunrise and sunset times in Birmingham on Day Number 130
(ii) The
theoretical amount of solar energy received by the solar array, if
exposed to 40% of the hours between sunrise and sunset on this
day
(iiI) The efficiency of its
solar panels.
Hour angle, 𝜔
t-12 24360°
t = time (hours) based on 24-hour clock
Zenith angle, 𝜃z
cos 𝜃z = sin𝛿 sin𝜙 + cos𝛿 cos𝜙 cos𝜔
Angle of declination, 𝛿
- 23.45
cosD+10365 X360°
Angle of incidence, 𝜃i
cos 𝜃i = cosδcosϕ-β+sinδ sinϕ-β