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answerhappygod
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Thank you.

Post by answerhappygod »

Thank you.
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Problem 1: Convert the voltage sources in Fig. 8.108 to current sources. R w 6 Ω E18 V E =9V R w 2.2 ΚΩ (a) (b) FIG. 8.108

Problem 2: Convert the current sources in Fig. 8.109 to voltage sources. 1.5 A 4.7 ΚΩ o 30ZR, R 0 ) 6 mA (a) FIG. 8.109

Problem 3: For the configuration in Fig. 8.111: a. Convert the current source and 6.8 resistor to a voltage source. b. Find the magnitude and direction of the current li. C. Find the voltage Vab and the polarity of points a and b. R2 w 6.82 R M 102 I = 2A E = 12 V R3 39 Q Vab 1 FIG. 8.111

Problem 4: Convert the voltage sources in Fig. 8.114 to current sources. a. Find the voltage Vab and the polarity of points a and b. b. Find the magnitude and direction of the current 13. 13 R2 212 RX32 Ω R3 w 612 12 Ω R4 Vab + E C9V E220 V 20 V + FIG. 8.114 .

Problem 5: For the network in Fig. 8.115: a. Convert the voltage source to a current source. b. Reduce the network to a single current source, and determine the voltage V1. c. Using the results of part (b), determine V2. d. Calculate the current l2. + V2 - R2 8 mA 2.2 ΚΩ VR, 36.8kQ )3 mA = 12 V FIG. 8.115
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