Note: that given R2 = 0.5 ohm is the actual rotor resistance, R2 referred to the stator side is 2 ohms. Please have work

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Note That Given R2 0 5 Ohm Is The Actual Rotor Resistance R2 Referred To The Stator Side Is 2 Ohms Please Have Work 1 (191.48 KiB) Viewed 44 times

Note: that given R2 = 0.5 ohm is the actual rotor resistance, R2 referred to the stator side is 2 ohms. Please have work reflect given solutions to receive thumbs up. Thanks! a. T = 60Nm, b. I = 8.878A, c. Tst = 168.52 Nm, d. Ist = 59.4A, e. L'i=88.4V, Vi=44.2V, Vi L-L = 76.5566V, f.a T = 60 Nm, f.b 12°= 11.9194 A using Vi’, f.c T2st(new)=144.581 Nm, f.d 12st(new)=40.4583A, g. Pr=2.4592e+3 W. Part h. can be ignored. A three-phase, 480 V, six-pole, Y-connected, 60 Hz, 10 kW induction motor is driving a constant torque load of 60 Nm. The parameters of the motor are: R1 = 0.42, R2 = 0.50, Xeq = 40, N1 /N2 = 2 A voltage is injected in the rotor circuit to reduce the motor speed by 40%. e. Calculate the magnitude of the injected voltage. f. Repeat (a) to (d) for the motor with injected voltage. g. Calculate the power delivered to the source of injected voltage. h. Determine the overall efficiency of the motor (ignore rotational and core losses).