Part A Find the cutoff frequency for the RL filter shown in the figure. (Figure 1) Express your answer with the appropri

[answerhappygod]

Part A Find The Cutoff Frequency For The Rl Filter Shown In The Figure Figure 1 Express Your Answer With The Appropri 1 (48.51 KiB) Viewed 52 times

Part A Find the cutoff frequency for the RL filter shown in the figure. (Figure 1) Express your answer with the appropriate units. 2 ? fc = 7.9796 Hz Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Figure < 1 of 1 Part B Calculate H (jw) at We 10 mH ΠΙ ΑΣΦI 1 ? m + H (we) = 까 ξ127 Ω Submit Request Answer Part

Calculate (w) at we Express your answer with the appropriate units. 團」? (w.) - Value Units Submit Request Answer Part D Calculate H (jw) at 0.2w.- Figure < 1 of 1 Η ΑΣΦ It ved ? H (10.2w.) - 10 mH Submit Request Answer m + 까 ξ127 Ω Part E Calculate 0 (jw) at 0.2we. Express your answer with the appropriate units.

Calculate (jw) at 0.2we. Express your answer with the appropriate units. ? (0.2wc) = Value Units Submit Request Answer Part F Calculate H (jw) at 5w Figure < 1 of 1 ΤΗ ΑΣΦ vec |H (35wc) = Submit 10 mH Request Answer m + ξ127 Ω 까 Part G Calculate (w) at 5we. Express your answer with the appropriate units.

Part 6 Calculate (jw) at 5w Express your answer with the appropriate units. ? 0 (5) - Value Units Submit Request Answer Part 1 If V; = 10cosut V, what is the steady-state expression for vo when w=we? Figure < 1 of 1 O 7.07 cos(12,700 +45) V 14.14 cos(25, 400 - 45°) V O 7.07 cos(12,700 – 45") V 10 mH m + 까 ξ127 Ω 7.07 cos(25, 400+ 45°) V 7.07 cos(25,400 – 45°) V 14.14 cos(12,700 - 45°) V 14.14 cos(25, 400+45") V 14.14 cos(12,700 + 45") V

What is the steady-state expression for u, when w = 0.2wc? O 19.62 cos(2540t – 11.31°) V 9.81 cos(2540t + 11.31") V O 9.81 cos(5080t - 11.31°) V 19.62 cos(5080t - 11.31°) V O 19.62 cos(2540t + 11.31°) V O 19.62 cos(5080t + 11.31°) V O 9.81 cos(5080t +11.31") V O 9.81 cos(2540t – 11.31°) V Submit Request Answer Figure < 1 of 1 Part J What is the steady-state expression for v, when w = 5w.? 10 mH m + O 1.96 cos(127,000+ - 78.69") V 까 ξ127 Ω O 1.96 cos(127,000t + 78.699) V O 3.92 cos(127,000+ + 78.69) V O 3.92 cos(127,000+ - 78.69°) V 106 19 K00+ 70 80 1

O 19.62 cos(2540++ 11.31°) V 19.62 cos(5080t + 11.31°) V O 9.81 cos(5080t + 11.31") V 9.81 cos(2540t – 11.31°) V Submit Request Answer Part J What is the steady-state expression for t), when w=5w? O 1.96 cos(127,000+ - 78.69°) V O 1.96 cos(127,000t + 78.69%) V Figure < 1 of 1 O 3.92 cos(127,000t + 78.69) V O 3.92 cos(127,000t – 78.69°) V O 1.96 cos(63,500t + 78.69') V O 3.92 cos(63,500t + 78.69°) V 10 mH m + O 3.92 cos(63, 500t – 78.69°) V 까 ξ127 Ω O 1.96 cos(63,500t – 78.69 ) V Submit Request Answer