P1 50 PTS In the given circuit valid fort 20*. 1,(t) = 2u_(t); R = 40; R = 20; C = 0.5F. The capacitor is initially char

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P1 50 Pts In The Given Circuit Valid Fort 20 1 T 2u T R 40 R 20 C 0 5f The Capacitor Is Initially Char 1 (45.31 KiB) Viewed 52 times

P1 50 PTS In the given circuit valid fort 20*. 1,(t) = 2u_(t); R = 40; R = 20; C = 0.5F. The capacitor is initially charged 50 v.(0)=3V a. Convert the circuit to the s-domain. Clearly label all circuit elements. ke 카 를 IG th OR ie 10 in alte WIPE 2 b. Use Nodal OR Mesh analysis to find i(t).t> 0 Clearly label all variables and indicate which method you want graded. Nodal on LEFT circuit: the single node equation is *+- (s+) () =*+- (s+) V() = ***V() = So: v(t) = (12-9%),(e) Then (t) =* = (2-). A Nodal on RIGHT circuit: the single node equation is So: v(t) = 12 - 9e Then 2 3 9/6 (4+ 68 +2 5 **(s+v6) -(s+) (3) - ****V(5)-23- = (12 - 9e"),(6) (8)="* = (2-4), () (A) Mesh on LEFT circuit: Label, the right loop, so that I =*- The single right-loop equation is (4+2+3).-(4+2) 1- = -16) = -1)= 4,60 50:6() = 2 -4(0)-(2-1),(0) (A) Mesh on RIGHT circuit: Label, the MIDDLE loop, so that I = -1, The single MIDDLE-loop equation is =) 96 (0) s+ $0: e(t) = 2-1() = (2-*)(0 (A) 2 23 65 +2 9 52 24-3-0-564-76 =24*4,09