| The original datagram diagrammed below enters a network with an MTU of 1812 bytes. IP ID 528 DF Flag 0 MF Flag 0 Offse

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answerhappygod
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| The original datagram diagrammed below enters a network with an MTU of 1812 bytes. IP ID 528 DF Flag 0 MF Flag 0 Offse

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The Original Datagram Diagrammed Below Enters A Network With An Mtu Of 1812 Bytes Ip Id 528 Df Flag 0 Mf Flag 0 Offse 1
The Original Datagram Diagrammed Below Enters A Network With An Mtu Of 1812 Bytes Ip Id 528 Df Flag 0 Mf Flag 0 Offse 1 (36.72 KiB) Viewed 34 times
CAN SOMEBODY CHECK MY ANSWERS FOR ME
| The original datagram diagrammed below enters a network with an MTU of 1812 bytes. IP ID 528 DF Flag 0 MF Flag 0 Offset 0 Data Size in bytes 5478 bytes a) What is the largest data size possible on the 1812 byte MTU network in bytes? 1812 B b) How many fragments are required to transmit the original datagram on the 1812 byte MTU network? 4|| c) Fill in the number of fragment blocks needed below for the number of fragments you found in b). For each fragment, fill in the values for the IP ID, DF Flag, MF Flag, Offset, and Data Size. IP ID DF Flag MF Flag Offset Data Size in bytes 528 0 1 0 1812 B 528 0 1 224 1812 B 528 0 1 448 1812 B 528 0 0 672 42 B
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