6. Consider values shown in the table below: P(H) p( EH) PEH) 1 (cold) 0.6 0.3 0.6 =2 (allergy) 03 0.8 0.9 =3 (stomach p

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6. Consider values shown in the table below: P(H) p( EH) PEH) 1 (cold) 0.6 0.3 0.6 =2 (allergy) 03 0.8 0.9 =3 (stomach p

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6 Consider Values Shown In The Table Below P H P Eh Peh 1 Cold 0 6 0 3 0 6 2 Allergy 03 0 8 0 9 3 Stomach P 1
6 Consider Values Shown In The Table Below P H P Eh Peh 1 Cold 0 6 0 3 0 6 2 Allergy 03 0 8 0 9 3 Stomach P 1 (34.64 KiB) Viewed 96 times
6. Consider values shown in the table below: P(H) p( EH) PEH) 1 (cold) 0.6 0.3 0.6 =2 (allergy) 03 0.8 0.9 =3 (stomach pain) 0.1 0.3 0.0 Those values represent (hypothetically) three mutually exclusive and exhaustive hypotheses for the patient's condition. For example, He the patient has a cold, Hx the patient has an allergy, and He the patient has stomach pain with their prior probabilities, p(H)'s and two conditionally independent pieces of evidence (E,patient sneezes and Es, patient coughs) which support these hypotheses to differing degrees. Therefore, a) Compute the posterior probabilities for the hypothesis if the patient sneexes. What is the conclusion that can be derived from this condition? b) Based on the answer from the previous result, as the patient coughs are now observed, compute the posterior probabilities for this condition. Explain the results. TY
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