= Consider the closed interval (-1, 1] with the subspace topology and the set X = {a,b,c,d) with -1
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= Consider the closed interval (-1, 1] with the subspace topology and the set X = {a,b,c,d) with -1
= Consider the closed interval (-1, 1] with the subspace topology and the set X = {a,b,c,d) with -1<x<.5 Tx = {X,, {a,b}}. Define the map y: (-1,1] → X by y(x) b.5<x< 1 Prove that y is x=.5 continuous but not a homeomorphism. = с =
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