An object attached to a spring undergoes simple harmonic motion modeled by the differential equation d²x + kr = 0 where

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An Object Attached To A Spring Undergoes Simple Harmonic Motion Modeled By The Differential Equation D X Kr 0 Where 1 (441.4 KiB) Viewed 42 times

An object attached to a spring undergoes simple harmonic motion modeled by the differential equation d²x + kr = 0 where x(t) is the displacement of the mass (relative to equilibrium) at time t, m is the d12 mass of the object, and k is the spring constant. A mass of 3 kilograms stretches the spring 0.7 meters. m Use this information to find the spring constant. (Use g = 9.8 meters/second?) k- 42 The previous mass is detached from the spring and a mass of 12 kilograms is attached. This mass is displaced 0.45 meters above equilibrium (above is positive and below is negative) and then launched with an initial velocity of 2 meters/second. Write the equation of motion in the form z(t) = ci cos(wt) + C2 sin(wt). Do not leave unknown constants in your equation. (t) = 45 cos VE X ما Rewrite the equation of motion in the form x(t) A cos(Bt – €). Do not leave unknown constants in T your equation. Leave o as an angle between and 2 2 TT x(t) =