A:[:)] if the square of a 2 x 2 matrix is identity, then either the matrix itself is identity or the matrix itself is ne
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A:[:)] if the square of a 2 x 2 matrix is identity, then either the matrix itself is identity or the matrix itself is ne
A:[:)] if the square of a 2 x 2 matrix is identity, then either the matrix itself is identity or the matrix itself is negative identity. = 1. If a 2 x 2 matrix A satisfies the property that A2 = 1, then we must have A2 – I = 0. 2. If A? – I = 0, then we must have (A+I)(A – I) = 0. 3. If (A+I)(A - 1) = 0, then we must have either A+I = 0 or A – I = 0. 4. If we must have either A+ 1 = 0 or A - I = 0, then we must have either A = -I or A=I. = Is this a correct solution? If yes, would the same proof work if A was a 3 x 3 matrix. If not, explain where the mistake is.
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