1. Show that 3105 + 4105 is divisible by 181. + 2. Show that 1! + 2! + 3! ++ 1000! = 3(mod 6).
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1. Show that 3105 + 4105 is divisible by 181. + 2. Show that 1! + 2! + 3! ++ 1000! = 3(mod 6).
1. Show that 3105 + 4105 is divisible by 181. + 2. Show that 1! + 2! + 3! ++ 1000! = 3(mod 6).
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