In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 6978 subjects rando

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899604
Joined: Mon Aug 02, 2021 8:13 am

In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 6978 subjects rando

Post by answerhappygod »

In a study of cell phone usage and brain
hemispheric​ dominance, an Internet survey was​ e-mailed
to 6978 subjects randomly selected from an online group
involved with ears. There were 1310 surveys returned. Use
a 0.01 significance level to test the claim that the return rate is
less than​ 20%. Use the​ P-value method and use the
normal distribution as an approximation to the binomial
distribution.
Question content area bottom
Part 1 Identify the null hypothesis and alternative
hypothesis.
A.
H0​:
p≠0.2
H1​:
p=0.2
B.
H0​:
p<0.2
H1​:
p=0.2
C.
H0​:
p=0.2
H1​:
p≠0.2
D.
H0​:
p​ = 0.2
H1​:
p<0.2
E.
H0​:
p>0.2
H1​:
p=0.2
F.
H0​:
p​ = 0.2
H1​:
p>0.2
The test statistic is
z=enter your response here.
​(Round to two decimal places as​ needed.)
The​ P-value is
enter your response here.
​(Round to three decimal places as​ needed.)
Because the​ P-value is

less than
greater than
the significance​ level,

fail to reject
reject
the null hypothesis. There is

sufficient
insufficient
evidence to support the claim that the return rate is less
than​ 20%.
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply