a Question : Let X be a random variable with a normal distribution N(M1,02), and Y a random variable with a normal distr

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899604
Joined: Mon Aug 02, 2021 8:13 am

a Question : Let X be a random variable with a normal distribution N(M1,02), and Y a random variable with a normal distr

Post by answerhappygod »

A Question Let X Be A Random Variable With A Normal Distribution N M1 02 And Y A Random Variable With A Normal Distr 1
A Question Let X Be A Random Variable With A Normal Distribution N M1 02 And Y A Random Variable With A Normal Distr 1 (145.77 KiB) Viewed 21 times
PLEASE SHOW THE WORKING OF EVERY PART!! THANK YOU :))
a Question : Let X be a random variable with a normal distribution N(M1,02), and Y a random variable with a normal distribution N(H2, oż). Consider a random sample of size nį from X and a random sample of size n2 from Y. Assume that X and Y are independent. = (a) Assuming that oỉ = oź = oʻ, show that the maximum likelihood estimator for o? is (nı – 1) sî + (12 – 1)s ni + n2 ô2 where 2-(X; - X) ni - 1 Σ2, (Υ; - Y)2 si and s 1 n2 - 1 (b) Assuming that oỉ + ož, show that the maximum likelihood estimators for oị and oź are: ô = (n1 – 1)sí ni (n2 – 1)s ôz = n2 (c) Let Lo be the likelihood function evaluated at the maximum likelihood estimators of o?, M1 and uz in part (a) and Ly be the likelihood function evaluated at the maximum likelihood estimators of o, o,Mi and uz in part (b). To test the hypothesis H. : 01 = 02 against H1 :01 + 02, we use the likelihood ratio Lo/Lj. Show that (@?)1/2(62)^2/2 A= (@2)(ni+n2)/2 A=
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply