Question 2 > A student was asked to find a 98% confidence interval for the proportion of students who take notes using d

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Question 2 > A student was asked to find a 98% confidence interval for the proportion of students who take notes using d

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Question 2 A Student Was Asked To Find A 98 Confidence Interval For The Proportion Of Students Who Take Notes Using D 1
Question 2 A Student Was Asked To Find A 98 Confidence Interval For The Proportion Of Students Who Take Notes Using D 1 (313.47 KiB) Viewed 25 times
Question 2 > A student was asked to find a 98% confidence interval for the proportion of students who take notes using data from a random sample of size n = 87. Which of the following is a correct interpretation of the interval 0.13 < p <0.31? Check all that are correct. The proprtion of all students who take notes is between 0.13 and 0.31, 98% of the time. There is a 98% chance that the proportion of the population is between 0.13 and 0.31. With 98% confidence, the interval between 0.13 and 0.31 contains the proportion of all students who take notes. With 98% confidence, the proportion of their classes a randomly selected student takes notes in is between 0.13 and 0.31. There is a 98% chance that the proportion of notetakers in a sample of 87 students will be between 0.13 and 0.31.
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