Q2) Given- 1 3 9 1/8 1/16 1/32 132 2 1/16 1/6 1/2 32 3 1/16 1/16 1/10 lic H 14 o fond, H(x, y), 4(x/y), H(81) Sell P (X1

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Q2 Given 1 3 9 1 8 1 16 1 32 132 2 1 16 1 6 1 2 32 3 1 16 1 16 1 10 Lic H 14 O Fond H X Y 4 X Y H 81 Sell P X1 1 (26.17 KiB) Viewed 22 times

Q2 Given 1 3 9 1 8 1 16 1 32 132 2 1 16 1 6 1 2 32 3 1 16 1 16 1 10 Lic H 14 O Fond H X Y 4 X Y H 81 Sell P X1 2 (25.63 KiB) Viewed 22 times

Q2 Given 1 3 9 1 8 1 16 1 32 132 2 1 16 1 6 1 2 32 3 1 16 1 16 1 10 Lic H 14 O Fond H X Y 4 X Y H 81 Sell P X1 3 (26.64 KiB) Viewed 22 times

Q2 Given 1 3 9 1 8 1 16 1 32 132 2 1 16 1 6 1 2 32 3 1 16 1 16 1 10 Lic H 14 O Fond H X Y 4 X Y H 81 Sell P X1 4 (30.58 KiB) Viewed 22 times

Q2 Given 1 3 9 1 8 1 16 1 32 132 2 1 16 1 6 1 2 32 3 1 16 1 16 1 10 Lic H 14 O Fond H X Y 4 X Y H 81 Sell P X1 5 (32.99 KiB) Viewed 22 times

Q2) Given- 1 3 9 1/8 1/16 1/32 132 2 1/16 1/6 1/2 32 3 1/16 1/16 1/10 lic H 14 o fond, H(x, y), 4(x/y), H(81) Sell P (X1, 15) 1 2 4 P(21) 1 + '/32-3 + 22 '18 + 116 + 132 + t 1/16 + 118 + 1/32 + + 116 + 1/16 1/16 + 1/32= + + 26 -11+र+ + 3 - + + + + 0 + - O + o PLUS) Ž + 1-15 + -10 on- * (x1) = 1/ 4, P (R2) = 4 P 1837-1, PCX4)= 1 / 4 1 Pry) = & PLB) = 1/2 PCG 3) = 1/3 , PCBU)= 1/3 +

4 H(x) = Cos (oxid 3 ) , T- I "2 Pearl til Boys + + + + T hl 41 601 4x = 103, h 4 1.103, I low 210g, log 13 a HEX)= 2 Н (ERIO Sol (SR2d 3 = (hah - 12: 当g + "四后十三四 109.2 + $ 109 4 + + 0,8 + 1 8+ D $0)+ (2) + $(3) + $(5) 11 + sot. =(RH

HC*,y)= 3.375 3.345 11 11 투를 뜯t 슬 (9무 +은 (+(674 + x + (* 읗 -- h 장 무 뚱to 끝 + gtoi 끝 +8 손 TE + 11 hi. 뿌 부 o 부 nx + | Gal x3 + 3 e3 - 4+ bolxo SA 0 teo 11 bal / CE 71/ 6014부 4부 60부 +부 CoP + Y Co꾸 " 메꾸 른 뜻 4부 C01뚜 C이은 4각 Ro 꾸 4 G + - + 꾸 + 4 = 뿌뜻 4기부 60부 + ear온 그 CRS Cor (03) 22 = ('XH

SELE = (RX7H'S (RH' =(*7H H(1x1 = 46,y)HLY) = 3.375 - 1.75 H (8/2) = 1.625 H(aly) = HLX19) - H(X) 3.3752 1:4(2/4)= 1.375 final answer :- HC x, y) = 3.375 H(279) = 1.375 H (81x1 1.625

from the previous data find the conditional relative entropy p(91%) D (P(91%) 119 (91x) = Pbeheer P4 V) Log Σ • Plyx (xlh b