A simple pendulum consists of a small object of
mass m= 1.52 kg hanging under a massless string
of length L= 8 m. The pendulum swings with
angular frequency ω=5.77 rads. If the mass is changed to
2 m and the length of the string is change to 6 L,
the frequency of this new pendulum becomes nω . What
is the value of n? Please round your answer
to 2 decimal places.
A Simple Pendulum Consists Of A Small Object Of Mass M 1 52 Kg Hanging Under A Massless String Of Length L 8 M The Pe 1 (25.98 KiB) Viewed 29 times
A simple pendulum consists of a small object of mass m = 1.52 kg hanging under a massless string of length L = 8 m. The pendulum swings with angular frequency w =5.77 rad. If the mass is changed to 2 m and the length of the string is change to 6 L, the frequency of this new pendulum becomes nw. What is the value of n? Please round your answer to 2 decimal places.
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!